Question

Graph the function. f(x)=2x^2-5 please help ill give you brainliest

Answer 1

f(x)=2x^2+0x-5

Find the vertex

0/4=0=x

Input x into the equation to find y or f(x)

0+0-5=f(x)

(0,-5) = Vertex

Now find a random x coordinate to input into the equation.

Let's do 4.

32+0-5=f(x)=27

It may not look like a parabola due to it being uneven.