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ludmilkaskok [199]
3 years ago
9

50 POINTS. A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t)=

-16t^2 + 64t + 4, where t is measured in seconds and h is the height in feet. What domain makes sense for this function
Mathematics
2 answers:
Morgarella [4.7K]3 years ago
7 0

Answer:

The domain that makes sense for this function is all values greater than or equal to 0.

Step-by-step explanation:

A ball is thrown into the air from a height of 4 feet at time <em>t</em> = 0. It is modeled by the function:

h(t)=-16t^2+64t+4

The domain of the function is time <em>t</em>. The range of the function is the ball's height in the air <em>h</em>.

Since time is our domain, we must restrict our domain to values equal to or greater than 0 since time cannot be negative.

Therefore, the domain that makes sense for this function is all values greater than or equal to 0.

In interval notation, this is:

[0, \infty)

And as an inequality:

t\geq 0

o-na [289]3 years ago
5 0

Answer:

[0, 4.061)

Step-by-step explanation:

This is not the actual domain of the parabola, but instead the stretch of domain which is found in quadrant I of the x, y coordinate plane, where in the physical world the event would actually occur.

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Two sides of a right triangle have the lengths 4 and 5. What is the product of the possible lengths of the third side? Express t
marishachu [46]

Answer:

19.2

Step-by-step explanation:

<u>1st Case:</u>

4 and 5 are legs of the right triangle.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+5^2=x^2

16+25=x^2

41=x^2

x=√41

√41 is about 6.4

x=6.4

<u>2nd Case</u>

5 is the hypotenuse of the right triangle and 4 is the legs.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+x^2=5^2

16+x^2=25

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<u>Final Step</u>

We need to multiply the two possible lengths for x. So for case 1 the length of x was 6.4 and for case two the length was 3. 6.4*3=19.2

Anwser: <u>19.2</u>

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