When 2.50grams of nacl is dissolved in 2liters of water what is the concentration of the solutuon
1 answer:
The concentration of the solution is also known as Molarity (M). The formula for molarity is
M = mol / liters
We already have the liters, so we only need to find moles. We can find the number of moles by using the molar mass of NaCl and the given amount. That can be found using the elements' atomic weights given on the periodic table.
22.990 (mass of Na) + 35.453 (mass of Chlorine) = 58.443 g / mol
That's how many grams are in one mole of NaCl, but we only have 2.5 grams. So, let's divide and see how many moles we have.
2.5 / 58.443 = .042776 moles
Now we can plug our numbers into the formula.
M = .02138 mols/L
So, your concentration is about .02 mol/L.
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The number of atoms present in 0.231 g of sodium is 6.02 x 10²¹ atoms.
The given parameters;
- <em>mass of the reacting sodium = 0.231 g</em>
- <em>1 mole of an atom = 6.02 x 10²³ atoms</em>
- <em>the atomic mass of sodium is 23 g/mol</em>
The number of moles of 0.231 g of sodium available is calculated as;
The number of atoms of 0.01 mole of sodium available is calculated as;
1 mole ---------- 6.02 x 10²³ atoms
0.01 ----------------- ?
= 0.01 x 6.02 x 10²³ atoms
= 6.02 x 10²¹ atoms.
Thus, the number of atoms present in 0.231 g of sodium is 6.02 x 10²¹ atoms.
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