Molecular formula consists of chemical symbols for constituent elements followed by the numeric subscripts describing number of the atoms of each element present in one molecule of the compound.
On the other hand, ionic compounds do not exist in the form of molecules. They are in the form of crystal lattice in the solid state which contains many ions each of cation and anion.
<u>Thus, a ionic compounds are unable to write a molecular formula. Empirical formulas to used to represent them.</u>
Considering the reaction stoichiometry and Avogadro's Number, the mass of barium chloride produced is 21.6 grams.
<h2>Balanced reaction</h2>
The balanced reaction is
2 HCl + Ba → BaCl₂ + H₂
<h2>Moles of HCl that react</h2>
Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.
Then you can apply the following rule of three: if 6.023×10²³ molecules are contained in 1 mole of HCl, then 1.25×10²³ molecules are contained in how many moles of HCl?
amount of moles of HCl= (1.25×10²³ molecules × 1 mole)÷ 6.023×10²³ atoms
<u><em>amount of moles of HCl= 0.2075 moles</em></u>
Then, 0.2075 moles of HCl react.
<h2>Reaction stoichiometry</h2>
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
HCl: 2 moles
Ba: 1 mole
BaCl₂: 1 mole
H₂: 1 mole
<h2>Mass of barium chloride produced</h2>
Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl produce 1 mole of BaCl₂, 0.2075 moles of HCl will produce how many moles of BaCl₂?
<u><em>amount of moles of BaCl₂= 0.10375 moles</em></u>
Being the molar mass of BaCl₂ 208.24 g/mole, then the mass of barium chloride produced is calculated as:
Finally, the mass of barium chloride produced is 21.6 grams.
It takes 83 mL of a 0.45 M NaOH solution to neutralize 235 mL of an HCl ... 2). You are titrating an acid into a base to determine the concentration of the base. The endpoint of the neutralization is reached but the stopcock on the buret sticks slightly ... 5). It takes 12.5 mL of a 0.30 M HCl solution to neutralize 285 mL of NaOH ...
Because the rock is irregularly shaped, you used the displacement method to measure its volume. You used <u>calculations</u> to indirectly find the <u>density</u> of the objects.