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F:\homework\math\<span>fraction_hw.docx</span>
The answer would be D. New Slide
Answer:
Question is incomplete.
Assuming the below info to complete the question
You have a collection of n lockboxes and m gold keys. Each key unlocks at most one box. Without a matching key, the only way to open a box is to smash it with a hammer. Your baby brother has locked all your keys inside the boxes! Luckily, you know which keys (if any) are inside each box.
Detailed answer is written in explanation field.
Explanation:
We have to find the reachability using the directed graph G = (V, E)
In this V are boxes are considered to be non empty and it may contain key.
Edges E will have keys .
G will have directed edge b1b2 if in-case box b1 will have key to box b2 and box b1 contains one key in it.
Suppose if a key opens empty box or doesn’t contain useful key means can’t open anything , then it doesn’t belongs to any edge.
Now, If baby brother has chosen box B, then we have to estimate for other boxes reachability from B in Graph G.
If and only if all other boxes have directed path from box B then just by smashing box B we can get the key to box b1 till last box and we can unlock those.
After first search from B we can start marking all other vertex of graph G.
So algorithm will be O ( V +E ) = O (n+m) time.
Answer:
Customer(1) - (1) Vehicle.
Explanation:
Cardinality is the mapping of entities or group of entities to a cardinal value. It tries to show the relationship between two objects like a cups in a shelf or plates in racks.
The car dealer in the question, sells one car to a customer and keep or prioritise the record of the main owner of the acquired vehicle. So the maximum cardinality assignment of the customer and vehicle is one (1) to one (1) mapping.
