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kkurt [141]
3 years ago
6

Write the function evens which takes in a queue by reference and changes it to only contain the even elements. That is, if the q

ueue initially contains 3, 6, 1, 7, 8 then after calling odds, the queue will contain 6, 8. Note that the order of the elements in the queue remains the same. For full credit, no additional data structures (queues, stacks, vectors, etc.) should be used. Assume all libraries needed for your implementation have already been included.
Computers and Technology
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

Explanation:

The following code is written in Java it goes through the queue that was passed as an argument, loops through it and removes all the odd numbers, leaving only the even numbers in the queue. It does not add any more data structures and finally returns the modified queue when its done.

  public static Queue<Integer> evens(Queue<Integer> queue) {

       int size = queue.size();

       for(int x = 1; x < size+1; x++) {

           if ((queue.peek() % 2) == 0) {

               queue.add(queue.peek());

               queue.remove();

           } else queue.remove();

       }

       return queue;

   }

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Answer:

The answer to the following questions can be given as:

Question: 1

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Question: 2

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Question: 3

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Explanation:

In question 1 the value of the foo variable is 1020 because we perform the string concat operation.

In question 2 Output of the code is false because float value keeps in binary and when we convert 0.1 or 0.2 to binary so it is not the same.

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