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Stock solution:
Concentracion bromide = 0.128 M
initial solution in volumetric flask = 450 µl
So , moles of bromide present:
450 µl in liters :
1 µl = = 1*10⁻⁶ liters
450 * ( 1*10⁻⁶ ) = 0.00045
0.128 * 0.00045 => 57.6 * 10⁻⁶ moles
Now volume final is 25 mL , in liters : 0.025 L ou 25*10⁻³
so new bromide concentration:
57.6*10⁻⁶ / 25*10⁻³=> 2.304*10⁻³ M
Answer: The enthalpy change for this reaction is 392 Joules
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
where,
n = number of moles
Now put all the given values in this expression, we get
Therefore, the enthalpy change for this reaction is 392 Joules
<u>1 mole of oxygen.</u>
Answer:
solution given:
according to the above reaction,1 mole of oxygen is required to react with 2 moles of sodium to form sodium peroxide.
Explanation:
Carbon Dioxide environmental gas so as to make carbonic corrosive that is consolidated with water. Carbon dioxide noticeable all around can disintegrate in rain water to frame carbonic corrosive, H2CO3. Carbonic corrosive is a powerless corrosive. It somewhat ionizes to frame hydrogen particles. The hydrogen particles from carbonic corrosive give common rain water a somewhat corrosive pH estimation of 5.6.
C. Decreasing the temperature
D. Raising the pressure
<h3>Further explanation</h3>
Given
Reaction
2SO₂+O₂⇔2SO₃+energy
Required
Changes to the formation of products
Solution
The formation of SO₃ is an exothermic reaction (releases heat)
If the system temperature is raised, then the equilibrium reaction will reduce the temperature by shifting the reaction in the direction that requires heat (endotherms). Conversely, if the temperature is lowered, then the equilibrium shifts to a reaction that releases heat (exothermic)
While on the change in pressure, then the addition of pressure, the reaction will shift towards a smaller reaction coefficient
in the above reaction: the number of coefficients on the left is 3 (2 + 1) while the right is 2
As the temperature decreases, the equilibrium will shift towards the exothermic reaction, so the reaction shifts to the right towards SO₃( products-favored)
And increasing the pressure, then the reaction shifts to the right SO₃( products-favored)⇒the number of coefficients is greater