Answer:
a) 2.29E4
Explanation: 1kg = 1000g. to get mass in grams multiply 22.9 kg by 1000g then divide by 1 kg to cancel the kg.
b) 2,29E5 g
c) 2.29 E10 μg
Answer:
The answer to your question is 510.7 kJ
Explanation:
Data
Q = ?
Volume = 2 L
Temperature 1 = T1 = 19°C
Temperature 2 = T2 = 80°C
Specific heat = 4.186 J/kg°C
Density of water = 1 g/ml
Equation
Q = mC(T2 - T1)
Process
1.- Calculate the mass of water
mass = density x volume
mass = 1 x 2000
mass = 2000 g
2.- Substitute values in the Heat formula
Q = (2000)(4.186)(80 - 19)
-Simplification
Q = (2000)(4.186)(61)
-Result
Q = 510692 J or 510.7 kJ
Answer:
False. One mole of a certain substance will always contain
atoms of that substance.
Explanation:
Hope this helped!
43.56 grams of are produced if 16g of CH4 reacts with 64g of O2.
Explanation:
Balance equation for the reaction:
CH4 + 2O2⇒ CO2 +2H2O
Data given : mass of CH4 =16 grams atomic mass = 16.04 grams/mole
mass of water 36 gram atomic mass = 18 grams/moles
mass of CO2=? atomic mass = 44.01 grams/mole
number of moles =
equation 1
number of moles in CH4
n = 
= 0.99 moles
Since combustion is done in presence of oxygen hence it is an excess reagent and methane is limiting reagent so production of CO2 depends on it.
From the equation
1 mole of CH4 gave 1 mole of CO2
O.99 moles of CH4 will give x moles of CO2
= 
x = 0.99 moles of carbon dioxide
grams of CO2 = number of moles x atomic mass
= 0.99 x 44.01
= 43.56 grams of CO2 is produced.