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3 years ago

Which equation represents the first electron affinity of chlorine?

1 answer:

7 0

Answer:
Option-A [Cl (g) + e⁻ → Cl⁻ (g)] is the correct answer.

Explanation:
First electron affinity is the amount of heat evolved when an electron is added to a neutral atom.
Such problems often come in questions related to Born-Haber Cycle topic. Let suppose Mg and Cl₂ is reacted to form MgCl₂ crystal.

Then the Cl₂ gas is first atomized as follow,

Cl₂ → 2 Cl

After atomization an electron is added to neutral chlorine atoms, as,

Cl + e⁻ → Cl⁻

So, option A is correct choice.

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The reaction between zinc (Zn) and hydrogen chloride (HCl) produces zinc chloride (ZnCl), hydrogen (H2) gas, and heat. If more h

andrew-mc [135]

If more heat is removed from the reaction the rate of reaction change as below to counter the action

The rate of the forward reaction increase and produces more zinc chloride

explanation

The reaction of zinc and HCl to produce ZnCl and H2 is exothermic reaction, heat is produced as one product and by removing heat it favor forward reaction

The position of equilibrium moves to the right since removing heat led to decrease of temperature and more zinc chloride is produced.

6 0

3 years ago

Which organic compound is isometric with at least one aldehyde?

azamat

D. Ketone :::::::::::

4 0

4 years ago

How do you know how many electrons will be gained by the ion TOF

Tom [10]

Answer:

i dont know

Explanation:

8 0

3 years ago

in heating a kettle of water on an electric stove, 3.34×10^3 J of thermal energy was provided by the element of the stove. yet,

insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, $H_{supplied}$ = 3.34 × 10³ J

The amount thermal energy gained by the kettle, $H_{absorbed}$ = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

$\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}} \times 100$

Therefore, we get;

$\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3} \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%$

The percentage efficiency of the electrical element, η% ≈ 82.186%.

4 0

3 years ago

In which of these diatomic molecules would you NOT find an octet of electrons

Semmy [17]

Answer:

The hydrogen molecule is the only one in which can not find an octet of electrons around each atom.

Explanation:

Let's evaluate each case.

1. Nitrogen (N₂):

With Z = 7, nitrogen has the following electronic configuration

1s²

2s² 2p³ → valence electrons

Since its valence electrons are 5, in the molecule one nitrogen atom shares 3 electrons with the other one, and each remains with an electron pair, so each atom has an octet of electrons.

2. Hydrogen (H₂):

With Z = 1, its electronic configuration is:

1s¹ → valence electron

In the molecule, the hydrogen atoms share the only electron they have, so they will have only 2 electrons around. In this diatomic molecule, we can not find an octet.

3. Oxygen (O₂):

Z = 8. Electronic configuration:

1s²

2s² 2p⁴ → valence electrons

In the diatomic molecule, each oxygen atom shares 2 electrons with the other one and remains with 2 pairs of electrons, therefore, each oxygen atom has an octet.

4. Fluorine (F₂)

Z = 9. Electronic configuration:

1s²

2s² 2p⁵ → valence electrons

In this molecule, each fluorine atom shares 1 electron with the other and remains with 3 pairs of electrons, hence, each fluorine atom has an octet of electrons around.

Finally, we can say that the hydrogen molecule is the only one in which can not find an octet of electrons around each atom.

I hope it helps you!

8 0

3 years ago