Answer:
The rate determining step is step 1
Explanation:
Answer:
Because the kind of compounds that you try to determine using paper chromatography (organic compounds) are usually not soluble in water. Furthermore, water could react chemically with some of this compounds, because it's a very reactive molecule. You need organic solvents that are mostly inert.
Answer:
20.19 amu.
Explanation:
From the question given above, the following data were obtained:
Isotope A:
Abundance (A%) = 90.5%
Mass of A = 20 amu
Isotope B:
Abundance (B%) = 9.5%
Mass of B = 22 amu
Average atomic mass =..?
The average atomic mass of the element can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
Average atomic mass = [(20 × 90.5)/100] + [(22 × 9.5)/100]
Average atomic mass = 18.1 + 2.09
Average atomic mass = 20.19 amu
Therefore, the average atomic mass of the element is 20.19 amu
Answer:
Did not understand your question
Explanation:
All I know is that:
Control variable is what you keep the same throughout all of the tests.
Dependant variable is what you observe from the test
Independent variable is what you are altering in the test