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aalyn [17]
4 years ago
15

In chickens the dominant allele Cr produces the creeper phenotype (having short legs). However, the creeper allele is lethal in

the homozygous condition. If two creepers are mated, what proportion of the living progeny will be creepers?
Biology
1 answer:
Svetllana [295]4 years ago
4 0

Answer:

66.6% of the living progeny would be creepers

Explanation:

The creeper allele is Cr for both parents this means that there is a 50% chance that they will pass the C or r trait to their progeny. In this scenario the deleterious inheritance of rr will be 25% so this will not be factored in this answer. The other progeny is CC 25% and Cr 50% for genotype only

The new calculation for living progeny is this: Of the chances of three living progeny there could be one normal CC and two creepers Cr. This means that 33.3% of the living progeny is normal CC and 66.6% of the living progeny are creepers Cr.

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____________________________________________________

Answer:

Your answer would be 13 cups of spaghetti sauce.

____________________________________________________

Explanation:

Lets break down this question to make the answer easier:

8 ounces = 1 cup

We are going to use the above to help us solve this question.

In your question, you have 26 ounces, and you would have four cups. You would need to calculate how many ounces are in the 4 cups

To do this, you would multiply 26 by 4:

26 × 4 = 104

The four cups have a total of 104 for ounces. But, you are not done solving yet. You need to found how many cups there are. We would be going to use the 8 ounces, since we know that is the amount of one cup, and use that to divide 104, since we need to distribute the amount of ounces to the cups.

You would divide 104 by 8

104 ÷ 8 = 13

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Your FINAL answer would be 13.

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<em>-Julie</em>

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