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antoniya [11.8K]
3 years ago
7

A proton and a deuteron are moving with equal velocities perpendicular to a uniform magnetic field. A deuteron has the same char

ge as the proton but has twice its mass. The ratio of the magnetic force on the proton to that on the deuteron is:
a. 0.5.
b. 1.
c. 2.
d. There is no magnetic force in this case.
Physics
1 answer:
Leokris [45]3 years ago
7 0

Answer:

option (b)

Explanation:

mass of proton, mp = m

mass of deuteron, md = 2m

charge on proton, qp = q

charge on deuteron, qd = q

The magnetic force on the charged particle when it is moving is given by

F = q v B Sinθ

where, θ is the angle between the velocity and magnetic field.

Here, θ = 90°

Let v is the velocity of both the particle when they enters in the magnetic field.

The force on proton is given by

Fp = q x v x B ...... (1)

The force on deuteron is

Fd = q x v x B .... (2)

Divide equation (1) by equation (2)

Fp / Fd = 1

Thus, the ratio of force on proton to the force on deuteron is 1 : 1.

Thus, option (b) is correct.

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Answer:

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Explanation:

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From Newton's equation of motion, we know that;

d = ut + ½at²

Thus,for first car, we have;

d = v1•t + ½(a1)t²

Plugging in the relevant values, we have;

d = 33t + 0

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For second car, we have;

d = v2•t + ½(a2)•t²

Plugging in the relevant values, we have;

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Since they meet at the next exit, then;

33t = ½(a2)t²

simplifying to get;

33 = ½(a2)t

Now, we also know that;

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a2 = (33 × 33 × 2)/2500

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3 years ago
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Alika [10]
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A magnetic field is uniform over a flat, horizontal circular region with a radius of 1.50 mm, and the field varies with time. In
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Answer:

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Answer:

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