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3 years ago

One student did an experiment to find if fertilizer can make plants grow taller. The steps of the experiment are listed below.

Physics

2 answers:

IgorC [24]3 years ago

3 0

C. because they did not use the same plant

Natali [406]3 years ago

3 0

Type of soil is the independent variable because it is the one that is being changed and the one that isn't affected by any other variables.

HOPE THIS HELPS

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Tsunami waves are usually created by earthquakes that occur along ? _____ _____

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Answer:

The correct answer is the sea

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3 years ago

Help ASAP thanks !!!

Ann [662]

Answer:

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Explanation:

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3 years ago

Phys-1A Horizontal Practice 2

krek1111 [17]

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2 years ago

a 3.00 kg block moving 2.09 m/s right hits a 2.22 kg block moving 3.92 m/s left. afterward, the 3.00 kg block moves 1.11 m/s lef

LuckyWell [14K]

The momentum of the 2.22 kg afterwards is 0.91 kg m/s to the right

Explanation:

We can solve this problem by applying the law of conservation of momentum.

In fact, the total momentum before and after the collision must be conserved. So, we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where:

$m_1 = 3.00 kg$ is the mass of the first block

$u_1 = 2.09 m/s$ is the initial velocity of the first block (we take the right as positive direction)

$v_1 = -1.11 m/s$ is the final velocity of the first block (to the left)

$m_2 = 2.22 kg$ is the mass of the second block

$u_2 = -3.92$ is the initial velocity of the second block

$v_2$ is the final velocity of the second block

Re-arranging the equation and substituting the values, we find: the final velocity of the second block:

$v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(3.00)(2.09)+(2.22)(-3.92)-(3.00)(-1.11)}{2.22}=0.41 m/s$

(to the right, since it is positive)

And so, the momentum of the 2.22 kg block afterwards is:

$p_2 = m_2 v_2 = (2.22)(0.41)=0.91 kg m/s$ (to the right)

Learn more about momentum here:

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brainly.com/question/9484203

#LearnwithBrainly

8 0

3 years ago

A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energ

skad [1K]

Mass of the diver (m) = 90 Kg.
Height of the board from the ground (h) = 10 m.
Acceleration due to gravity (g) = 9.8 m/s^2.
Height of the diver from the ground when he reaches point C (x) = 5m
Initial velocity (u) = 0 m/s
We know, gravitational potential energy of a body = mass × acceleration due to gravity × height.
Therefore, the gravitational potential energy of the diver when he reaches point C (GPE) = mg(h - x)
or, GPE = [90 × 9.8 × (10-5)] J
or, GPE = [90 × 9.8 × 5] J
or, GPE = 4410 J
For a freely falling body,
v^2 - u^2 = 2gh
or, v^2 = 2gh
We know, kinetic energy of a body = 1/2 mv^2
Therefore, kinetic energy of the diver when he reaches point C (KE) = 1/2 m(2gx)
Here, 2gx = (2 × 9.8 × 5) = 98 (m/s)^2
We have already seen v^2 = 2gh
or, v = √2gh
So, the velocity of the diver = √2gx = √98 m/s = 9.9 m/s

Answers:

The gravitational potential energy of the diver when he reaches point C is 4410 J.

The velocity of the diver is 9.9 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

5 0

2 years ago

Read 2 more answers