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Gre4nikov [31]
3 years ago
5

Anthony grew 64 plants with 32 seed packets.How many seed packets does Anthony need to have a total of 90 plants in his backyard

. Unit rate word problem. I need it ASAP
Mathematics
1 answer:
adelina 88 [10]3 years ago
8 0
Let the total seed packets needed Anthony to have 90 plants be x.

then,
64:32 :: 90:x
2:1 :: 90:x
90 = 2x
x = 45 seed packets.

________________________

64 plants = 32 seed packets.
1 plant = \frac{32}{64} = \frac{1}{2} seed packets.

90 plants = \frac{1}{2} \times 90 = 45 seed packets.

Anthony need 45 seed packets to have 90 plants.

!! Hope It Helps !!
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A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th
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Answer:

x^2 + 15x - 60 = 0

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

(x + 15)\ by\ x

Area = 60in^2

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

Area = Length * Width

60= (x + 15) * x

Open Bracket

60= x^2 + 15x

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x^2 + 15x - 60 = 0

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Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where

a = 1

b = 15

c = -60

So:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}

x = \frac{-15 \± \sqrt{225 + 240}}{2}

x = \frac{-15 \± \sqrt{465}}{2}

x = \frac{-15 \± \21.56}{2}

Split:

x = \frac{-15 + 21.56}{2} or x = \frac{-15 - 21.56}{2}

x = \frac{6.56}{2} or x = \frac{-36.36}{2}

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But length can't be negative;

So:

x = 3.28

The actual dimensions: (x + 15)\ by\ x is

Length =3.28 +15

Length =18.28

Width = x

Width =3.28

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