Answer: 110
Step-by-step explanation:
Given;
Total cost C = $151
Enrollment fee E = $30
Charge per 10 test t = $11
n is the number of packet of test taken.
The questions can be represented by the equation below;
30 + 11n = 151
Substracting 30 from both sides.
11n = 151-30 = 121
n = 121/11
n = 11
Since the number of packet of test is 11 and each packet contains 10 tests. The number of test N is given by;
N = 10 n = 10 ×11 = 110
N = 110
Answer:
9
Step-by-step explanation:
The reciprocal of 1/9 is 9/1 which is just 9.
We use the distance formula for this problem.
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
The distance between point (-2,-2) and point (-2,4).
d = √[(⁻2 - ⁻2)² + (4 - ⁻2)²] = 6 units
Then, compute for 20% of 6 units:
Distance traveled = 6(0.2) = 1.2 units
Use 1.2 units as distance and the starting point (-2,-2). The x-coordinate should still be at -2 because the distance is a straight line as shown in the picture.
1.2 = √[(-2 - ⁻2)² + (y - ⁻2)²]
Solving for y,
y = -0.8
The point is found at (-2,-0.8). This is located at quadrant 3. As to the distance traveled, that would be: 1.2*6 = 6 miles. Thus, the answer is C.
Answer:
X=70
Step-by-step explanation:
70 + 75 + 35 =180
x + x+5 + x-35
- 4(1/2)x - (3/7) = (1/4)
- 4(1/2)x = (1/4) + (3/7)
- (9/2)x = (7+12)/28
-(9/2)x = 19/28
x = (19/28) * 2 / 9
x = (19/14) / 9
x = 19 / (14*9)
x = 19 / 126
