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Ierofanga [76]
2 years ago
10

Is a data set has 10 values, with a mean of 75, and a variance of 11, what is the standard deviation?

Mathematics
1 answer:
harina [27]2 years ago
3 0
Awdawdawdawdadwawdawdjahsduoahwdoahw
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The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers
stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

(c) Confidence Interval for male expenditure is ($106.40, $136.40)

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

(c) Male

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

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3 years ago
What is the answer for<br> 3(x-2)+6x=3x-2+6x
Rudiy27
I think this attachment will help you

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2 years ago
I like cheese burger do u liek cheese burgers 2+2+12-21+492
andre [41]
Yes bananannanejdjdbe evehsosnsbscwhwje shekels s
4 0
1 year ago
I don’t understand this, can someone please explain and show the answers please
OLga [1]

your answer would be A. 122/27

3 0
2 years ago
Which expression gives the distance between the points<br> (-3, 4) and (6,-2)?
stepan [7]

Answer:43

Step-by-step explanation:

3 0
3 years ago
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