#1
That is false..one could have side lengths of 9 and 1, and the other could have side lengths of 3. Both the areas would be 9, but the figures would not be congruent.
#2
That is true, they must both have the same side length to have the same perimeter, therefore they will also have the same area.
ANSWER
The correct answer is C
EXPLANATION
We want to find the quotient:

We multiply by the reciprocal of the second fraction:

We cancel out the common factors to obtain:

We multiply to get

This simplifies to :

The correct answer is C
So, 9 out of 10 students prefer class, so, obviously, it would not be 100. It would be 150. So in conclusion, 50 students prefer lunch over math class, whilst 150 other students prefer math class over lunch.
Answer:
Step-by-step explanation:
∩
is asking for the intersection of sets
and
, or simply, which numbers can be found in both sets.
The numbers shared between the two sets are
.
Next, we need to union this result with the set
, or simply, combine the numbers in both sets together.
This would result in 
For E the answer is 2. Because the square of 1 is one and 9 is three. And 2 to the square root of two which would be 2 time 2= 4