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Natali5045456 [20]
3 years ago
15

40 percent of 1000000

Mathematics
1 answer:
OverLord2011 [107]3 years ago
8 0
<span>40% of 1000000 is 400000. </span>
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What is the area of the parllelogtam shown below
Umnica [9.8K]
<h3>Answer: 16 square units</h3>

Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5

a^2 + b^2 = c^2

3^2 + x^2 = 5^2

9 + x^2 = 25

x^2 = 25-9

x^2 = 16

x = sqrt(16)

x = 4

This is a 3-4-5 right triangle.

The height of the parallelogram is 4 units.

We have enough info to find the area of the parallelogram

Area of parallelogram = base*height

Area of parallelogram = 4*4

Area of parallelogram = 16 square units

Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.

6 0
3 years ago
Solve A = 1/2bh, for b
Kitty [74]

Answer:

b=2A/h

Step-by-step explanation:

First I throw everything else to another side with A by dividing them

(A = b)/2h

then I get

b=2A/h

7 0
3 years ago
Read 2 more answers
Solve for x radical forms
vova2212 [387]

Answer:

in right angled triangle ABC

by using Pythagoras law

h²=p²+b²

x²=7²+10²

x=√149=12.21cm

8 0
3 years ago
If f(x) = 3x +9 x when f(x) = 30
den301095 [7]

Answer:

x=5/2

Step-by-step explanation:

When f(x)=30, we have 3x+9x=30.

Combining like terms on the right side, we have 12x=30.

Finally, dividing by 12 we get x=30/12.

We note that 30=6*5 and 12=6*2, so 30/12=5/2.

So, \boxed{x=5/2} and we're done!

3 0
2 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
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