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boyakko [2]
3 years ago
12

NEED HELP IMMEDIATELY

Mathematics
2 answers:
lesya [120]3 years ago
5 0

Answer:

(13, −1)

Step-by-step explanation:

Both figures will have the same transformation applied.

We can see from JKLM and J'K'L'M' that the transformation is a translation 7 units right and 5 units up.

Point T has coordinates (6, -6).  Applying this translation, we would have T' at (6+7, -6+5) = (13, -1).

Karo-lina-s [1.5K]3 years ago
4 0
I'm sorry, but this doesn't make sense. Point T is nowhere near any of the given coordinates. I could be really bad at graphs, for all I know, but I'm just telling you what I know.
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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0
3 years ago
Read 2 more answers
Solve the simultaneous equations:<br><br> 3a-2b=14 <br> 12a+9b=39
kirill [66]
Use elimination
Multiply first equation by 4
12a - 8b = 56
12a + 9b = 39
Subtract both
-17b = 17
b = -1
Plug in -1 for b
3a - 2(-1) = 14
3a = 12, a = 4
Final answer: a = 4, b = -1
5 0
3 years ago
Please can someone prove this equation
zubka84 [21]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1

Consider the left side

2cos²A - 1 ← replace 1 by sin²A + cos²A

= 2cos²A - ( sin²A + cos²A)

= 2cos²A - sin²A - cos²A

= cos²A - sin²A = right side ⇒ verified



6 0
3 years ago
How is adding 0.267 to 50.9 different from adding 0.26 to 50.9
Brut [27]

Answer:

Step-by-step explanation:

They are different numbers:

0.269 + 50.9 = 51.169

0.26 + 50.9 = 51.16

8 0
3 years ago
What is one true mathematical statement involving exponents I could make out of 5, 25, and 2?
pentagon [3]

Answer:

5^2 x 2^0 = 25 or 5^2 = 25

Step-by-step explanation:

5^2 = 25

2^0 = 1 (Anything raised to the zero power equals one no matter what the number is)

25 x 1 = 25

8 0
3 years ago
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