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Pavel [41]
2 years ago
15

Solve How many mm are in 12 km? 12 km = mm

Mathematics
2 answers:
kompoz [17]2 years ago
7 0

Step-by-step explanation:

ieieiefididiidododododkdjdjdjdjdjdjdkdjdid

anygoal [31]2 years ago
5 0
12 kilometers =
12000000 millimeters


Mark brainliest please


Hope this helps you
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Pre Calculus Help! Will give Brainliest!
Sveta_85 [38]
It's a quotient identity
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3 years ago
"at the end of the year Juan has $52.71 more than 4 times his balance at the beginning of the year if his ending balance was $17
Salsk061 [2.6K]
At the end of the year, Juan has 52.71 more than 4 times his balance at the beginning. Okay, let's set this up.

4x + 52.71
(4 times) (52.71 more)
His ending was 172.90, so
4x + 52.71=172.90
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He had $30.05 at the beginning of the year.
8 0
3 years ago
Which equation can be used to solve the problem?
const2013 [10]

Answer:

10 * 50%

Step-by-step explanation:

It is simple

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3 0
2 years ago
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
HELP PLEASE,
faltersainse [42]
I think it's D but make it sire
7 0
3 years ago
Read 2 more answers
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