Could Someone give me a run down of how these problems are done? i used a calculator to get the answers but now i want to know h
ow to do these on my own
1 answer:
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Answer:
The 95% confidence interval for the population mean rating is (5.73, 6.95).
Step-by-step explanation:
We start by calculating the mean and standard deviation of the sample:
We have to calculate a 95% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=6.34.
The sample size is N=50.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
The degrees of freedom for this sample size are:
The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
The 95% confidence interval for the mean is (5.73, 6.95).
Answer:
The value of test statistic is 1.338
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 16.000
Sample mean, = 16.218
Sample size, n = 22
Alpha, α = 0.05
Sample standard deviation, s = 0.764
First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Thus, the value of test statistic is 1.338