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Ad libitum [116K]
3 years ago
15

Which angle is not supplementary to 6 2 4 5 8

Mathematics
1 answer:
Slav-nsk [51]3 years ago
7 0
I thinks the answer is 5
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△QRS is rotated about point P to △Q′R′S′ . Which statements are true about the pre-image and image?
yuradex [85]

Note that rotation will not affect the shape and size of an object.

Rotation with respect to a point preserves the corresponding sides and the corresponding angles of the original image.

Hence, the statements

The corresponding angle measurements in each triangle between the pre-image and the image are preserved and

The corresponding lengths, from the point of rotation, between the pre-image and the image are preserved

are true.

3 0
3 years ago
I need help on this parallelograms question.
yarga [219]
180-132+x-6x+12=0
48+x-6x+12=0
48-5x+12=0
60-5x=0
-5x=-60
x=12
3 0
3 years ago
Read 2 more answers
The vector v⃗ in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.
allsm [11]

The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis is: (0, -1/2, √3/2).

<h3>Vector</h3>

a. Vector (v)

Vector (v)=v (cos Ф, sin Ф)

V=1 while the counterclockwise angle that is measured from positive x=Ф=π/4

Hence:

Vector=3(cos π/4, sinπ/4)

Vector=(3/√2, 3√2)

b. Vector w:

Vector w=1(0, cos 2π/3, sin2π/3)

Vector w=(0, -1/2, √3/2)

Therefore the vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector ws: (0, -1/2, √3/2).

The complete question is:

Resolve the following vectors into components:

a. The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.

(b) The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis.

Learn more about vector here:brainly.com/question/25705666

#SPJ1

5 0
2 years ago
Find the inverse of ????−7 −2
Masja [62]

Answer:

A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

Step-by-step explanation:

A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}

det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1

A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}

Hence, confirmed

6 0
4 years ago
How many possible solutions could f(x) = 6x^3 + 8x^2 - 7x -3 have?
Alex17521 [72]
3 possible solutions.


The reason is because of the degree, which is 3
3 0
3 years ago
Read 2 more answers
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