Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
x=4.956 im pretty sure
Step-by-step explanation:
Answer:
i think 22
Step-by-step explanation:
9*22=198
This is the<u> distributive property of multiplication</u> but tricky
the distributiver property says
a(b+c)=ab+ac
7=5+2
6(5+2)=(6 times 5)+(6 times 2)
Answer:
Step-by-step explanation:
Total marble = 8+5+4 = 19
n(Y) = 8, n(B) = 4 and n(R) = 5
Prob(R) = 5/17
Prob(B) = 4/16 {one marble is pulled out already}
Prob(R and B) = 5/17 × 4/16
= 5/17 × 1/4
= 5/68
