1st equation: 6m +5v = 56
2nd equation: 2m + 3v = 26
multiply 2nd eq. by 3
3rd equation = 6m +9v =78
subtract 1st from 3rd: 4v = 22
v = 22/4 = 5.5 so videos cost 5.50 each
now use 1st eq. to solve for m:
6m +5(5.50) = 56 =
6m + 27.50 = 56=
6m = 28.5
m = 28.5/6 = 4.75 each movie
video cost 5.50
movie cost 4.75
Answer:
the question is not clear dear
1-5+16=6p-3p
12=3p
p=4
*does that make sense? if not lmk and i can explain more!
Answer:
![4x^2-10x+11+\frac{6}{2x+5}](https://tex.z-dn.net/?f=4x%5E2-10x%2B11%2B%5Cfrac%7B6%7D%7B2x%2B5%7D)
Step-by-step explanation:
The given functions are:
and ![g(x)=2x+5](https://tex.z-dn.net/?f=g%28x%29%3D2x%2B5)
By algebraic properties of functions;
![\frac{f(x)}{g(x)}=\frac{8x^3-28x+61}{2x+5}](https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%29%7D%7Bg%28x%29%7D%3D%5Cfrac%7B8x%5E3-28x%2B61%7D%7B2x%2B5%7D)
We perform the long division of the two polynomials as shown in the attachment.
Therefore:
![\frac{8x^3-28x+61}{2x+5}=4x^2-10x+11+\frac{6}{2x+5}](https://tex.z-dn.net/?f=%5Cfrac%7B8x%5E3-28x%2B61%7D%7B2x%2B5%7D%3D4x%5E2-10x%2B11%2B%5Cfrac%7B6%7D%7B2x%2B5%7D)
The last choice is correct
it is an irrational not sure but i don't believe that it could be put in an ratio, so I say an irrational number