Answer:
x>2
Step-by-step explanation:
Step 1: Subtract 60x from both sides.
100x−200−60x>60x−120−60x
40x−200>−120
Step 2: Add 200 to both sides.
40x−200+200>−120+200
40x>80
Step 3: Divide both sides by 40.
40x/40> 80/40
x>2
Hope this helped :)
Answer:
r = p(-b/a)
Step-by-step explanation:
Let p(x) = q(x)(ax + b) + r(x) where q(x) is the quotient when p(x) is divided by ax + b and r(x) is the remainder.
Since ax + b is a first degree polynomial, r(x) is one power less than ax + b is is just a constant, r.
So, p(x) = q(x)(ax + b) + r
Now, p(x) = r when q(x)(ax + b) = 0
since q(x) ≠ 0, ax + b = 0 ⇒ ax = -b ⇒ x = -b/a
⇒ p(x) = r when x = -b/a
So, r = p(-b/a)
So, the remainder when a polynomial function p(x) is divided by a first degree polynomial ax + b is p(-b/a)
Answer:
0,4
Step-by-step explanation:
