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3 years ago

Solve the following inequality. −1

Mathematics

2 answers:

erica [24]3 years ago

7 0

Answer:

any thing, not 1 or -1

Step-by-step explanation:

the equality to any number is either itself or its opposite 1 inequality would be 2-infinite or -2- -infinite and zero

vitfil [10]3 years ago

5 0

Any thing not -1 or 1

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Find the value of X.

tatuchka [14]

This is the correct answer

4 0

1 year ago

How many decimeters are in 3.5 dekameters? Use the metric table to help answer the question.

Ivahew [28]

350 decimeters are there in 3.5 decameter

Solution:

We have to find the decimeters in 3.5 decameters

Use the metric table:

1 kilometre (km) = 10 Hectometres (hm) = 1000 m

1 Hectometre (hm) = 10 Decametres (dcm) = 100 m

1 Decametre (dcm) = 10 Metres (m)

1 Metre (m) = 10 Decimetres (dm) = 100 cm = 1000 mm

1 Decimetre (dm) = 10 Centimetres (cm)

1 decimeter = 0.1 meter

1 Centimetre (cm) = 10 Millimetres (mm)

1 centimeter = 0.01 meter

1 millimeter = 0.001 meter

From above metric table, we find that

100 decimeter = 1 decameter

Then, convert 3.5 decameter to decimeter

100 x 3.5 decimeter = 3.5 x 1 decameter

350 decimeter = 3.5 decameter

Thus 350 decimeters are there in 3.5 decameter

5 0

3 years ago

cathy and helen were racing each other from the same point and running in the same direction. the distance that cathy runs(in me

telo118 [61]

Step by step explanation

8 0

3 years ago

In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen

Mashcka [7]

Answer:

a) P' = P

$P(t) = 24e^{0.693t}$ where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

$\frac{dP}{dt} = P$

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

$P(t) = P_0e^{kt}$

where $P_0 = 24$ is the initial population

After 6 month (t = 1), the population is doubled to 48

$P(1) = 24e^k = 48$

$e^k = 2$

$k = ln(2) = 0.693$

Therefore $P(t) = 24e^{0.693t}$

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

$24e^{0.693t} = 1000000$

$e^{0.693t} = 1000000 / 24 = 41667$

$0.693t = ln(41667) = 10.64$

$t = 10.64 / 0.693 = 15.35$

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. $P' = P_0ke^{kt}$

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

$24e^{0.5k) = 48$

$0.5k = ln2 = 0.693$

$k = 1.386$

Therefore, $P' = 1.386*24e^{1.386t}$

At the mid of the 3rd year, where t = 2.5, we can calculate P'

$P' = 1.386*24e^{1.386*2.5} = 1064.67$ rabbits/year

4 0

3 years ago

The vertex of a quadratic function is (6, 2), and the y-intercept of the function is (0, −70). The equation of the function in v

rosijanka [135]

Answer:

-6

Step-by-step explanation:

-6

5 0

2 years ago