Answer:
3000 bags
Step-by-step explanation:
In this case we must apply the formula of the mean, which would be the sum of the values divided by the amount of data is the mean:
m = (a1 + a2 ... an) / n
In this case we know the mean, we must know the 1987 data, therefore:
Let x be the number of bags sold in 1987, replacing in the previous equation:
2100 = (1800 + 1500 + x) / 3
2100 * 3 = 3300 + x
x = 6300 - 3300
x = 3000
Therefore, for the average to be a total of 2100 bags in those 3 years, the amount of bag sold in 1987 must have been 3000 bags
Since car 4 travels at twice the rate, it travels twice the distance in the same amount of time. So, time column of the two tables will be the same, and the right column of car 4 will be twice the right column of car 2.
Answer:
B) -350
Step-by-step explanation:
We are given the sequence:
-56, -59, -62, -65...
And we want to determine its 99th term.
First, note that we have an arithmetic sequence. This is because each subsequent term differs from the previous term by a common difference.
In this case, each subsequent term is 3 less than the previous term, so our common difference <em>d</em> is -3.
To find the 99th term, we can write an explicit formula. The explicit formula for an arithmetic sequence is:
![x_n=a+d(n-1)](https://tex.z-dn.net/?f=x_n%3Da%2Bd%28n-1%29)
Where <em>x_n</em> represents the <em>n</em>th term, <em>a</em> is the initial term, and <em>d </em>is the common difference.
Since the first term is -56, <em>a </em>= -56.
By substitution, we acquire:
![x_n=-56-3(n-1)](https://tex.z-dn.net/?f=x_n%3D-56-3%28n-1%29)
The 99th term is when <em>n</em> = 99. Thus:
![x_{99}=-56-3(99-1)](https://tex.z-dn.net/?f=x_%7B99%7D%3D-56-3%2899-1%29)
Evaluate:
![x_{99}=-56-3(98)=-56-294=-350](https://tex.z-dn.net/?f=x_%7B99%7D%3D-56-3%2898%29%3D-56-294%3D-350)
Our answer is B.
Answer:
119 bracelets
Step-by-step explanation:
623-28= 595
595/5 = 119