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inn [45]
3 years ago
10

Whats 2.3

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

\frac{7}{3}

Step-by-step explanation:

We require 2 equations with the repeating decimal after the decimal points.

let x = 2.3333... → (1) ← multiply both sides by 10

10x = 23.333..... → (2)

Subtract (1) from (2), thus eliminating the repeating decimal

9x = 21 ( divide both sides by 9 )

x = \frac{21}{9} = \frac{7}{3}

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Need help ASAP mid term . <br> - 60 points
Ivahew [28]

the metal bar/random line is almost the same size as the other two sides of the triangle. if one side is 32ft, then the opposite side is 32ft also. the bottom is 100ft, so we could eliminate C. because it couldnt be that number. now the bottom triangle, one side is 40ft so the other side has to be 40ft as well. its asking about the metal bar.

its either:

A. 53.2ft     or

B. 44.4

because the line is almost the same size as 32ft. its almost a equallateral triangle. i would go with A. though because if you imagine the line at the bottom of the line (100ft.) the line would go over half of it (and 53.2 is over half of 100) so i would say

A.53.2

if this didnt help let me know. and i will delete this (if i can-)

7 0
3 years ago
Which of the following two statements are truly of ordinary whole-life insurance policies?
e-lub [12.9K]
I believe it is the last 2
3 0
4 years ago
Assume that the probability that a baseball player will get a hit in any one at bat is 0.250. What is the probability that he wi
Yanka [14]

Answer: 0.0791

Step-by-step explanation:

Given : The probability that a baseball player will get a hit in any one at bat is 0.250.

Let x be the first hit.

According to the geometric probability , the probability that x (th) trial is the first success =P(X=x)=(1-p)^{x-1}p , where p is the probability of getting success in each trial.

As per given p= 0.250

Then, the probability that he will get his first hit on his 5th at bat will be :

P(X=x)=(1-0.25)^{5-1}(0.25)\\\\=(0.75)^4(0.25)\\\\=0.0791015625\approx0.0791

Hence, the probability that he will get his first hit on his 5th at bat is 0.0791 .

7 0
3 years ago
Help! I will mark you the brainest !! ☺️☺️
Marizza181 [45]

Answer:

Part 1)  0.675\%

Part 2) 475\%

Part 3) 8\%

Part 4) \frac{67}{20}

Part 5) 2.65

Step-by-step explanation:

Part 1) Write as a percent 0.00675

we know that

To write a number as a percent, multiply the number by 100

so

0.00675*100=0.675\%

Part 2) Write as a percent 4 3/4

Convert mixed number to an improper fraction

4\frac{3}{4}=\frac{4*4+3}{4}=\frac{19}{4}

we know that

To write a fraction as a percent, multiply the fraction by 100

\frac{19}{4}*100=19*25=475\%

Part 3) Write as a percent 2/25

we know that

To write a fraction as a percent, multiply the fraction by 100

\frac{2}{25}*100=2*4=8\%

Part 4) write as a fraction 335%

we know that

335\%=\frac{335}{100}

Simplify

Divide by 5 both numerator and denominator

\frac{335}{100}=\frac{67}{20}

Part 5) Write as a decimal 265%

we know that

265\%=\frac{265}{100}=2.65

3 0
3 years ago
50. At a booth at the school carnival in past years, they've found that 32% of students win a stuffed toy ($3.25), 10% of studen
kipiarov [429]

Answer:

The expected amount to be paid by the carnival committee for prices would be $366.80

Step-by-step explanation:

Hello!

Here, we want to calculate the amount of money the carnival committee is expected to pay for the prizes for that booth

From the question, we have 3 categories of prices to be won

To calculate for people that won’t win anything , we simply subtract the percentages of all from 100

That would be 100-32-10-8 = 100-50 = 50%

So now let’s calculate the number of people out of 200 that will win each category based on the percentages

For stuffed toy

32/100 * 200 = 64

Jump rope

10/100 * 200 = 20

For t-shirt

8/100 * 200 = 16

So total price paid for stuffed toy= 3.25 * 64 = $208

For jump rope, we have 1.7 * 20 = $34

For t-shirt , we hav 16 * 7.8 = $124.8

So the total value spent on prices by the committee would be;

124.8 + 34 + 208 = $366.80

5 0
3 years ago
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