Isaac’s television is 25 inches wide and 18 inches high. What is the diagonal size of Isaac’s television? Round to the nearest t

Question

Alik [6]

4 years ago

10

Isaac’s television is 25 inches wide and 18 inches high. What is the diagonal size of Isaac’s television? Round to the nearest t

enth if necessary.

Mathematics

2 answers:

ikadub [295] · Answer 1 · 2021-12-01T14:19:54+03:00

Answer:

Step-by-step explanation:

The television takes the shape of a rectangle whose width is 25 inches and whose height is 18 inches. To determine the length of the diagonal, we will apply Pythagoras theorem. It states that

Hypotenuse^2 = opposite^2 + adjacent^2

From the given information,

Adjacent side = 25 inches

Opposite side = 18 inches

Diagonal = hypotenuse.

Therefore

Diagonal^2 = 25^2 + 18^2

Diagonal^2 = 625 + 324 = 949

Take square roots of both sides of the equation, it becomes

Diagonal = √949 = 30.805 inches

Approximately 30.8 inches to the nearest tenth.

ololo11 [35] · Answer 2 · 2021-12-01T16:10:06+03:00

ololo11 [35]4 years ago

3 0

Answer:

30.8

Step-by-step explanation: