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kenny6666 [7]
3 years ago
9

Identify the vertex of the parabola given by f(x) = (x + 2)^2 – 4

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

The vertex is ( -2, -4)

Step-by-step explanation:

The vertex form is

y = a( x-h) ^2 +k

where ( h,k) is the vertex

f(x) = (x + 2)^2 – 4

Rewriting

f(x) = (x -  -2)^2 – 4

The vertex is ( -2, -4)

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The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f
WITCHER [35]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)\\C=6\pi\ cm

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

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3 years ago
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If you're just asking for how that'd look in algebraic form then the answer would be v+50/2
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Step-by-step explanation:


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<h3>Answer:  11.55 liters</h3>

=================================================

Work Shown:

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1 cup = 0.275 L

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He drinks 1.65 L per day, so over 7 days he drinks a total of 7*1.65 = 11.55 liters.

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