Answer:
noted, thanks for the note
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
1. x= 8
2. x= 6
3. x= 7
4. x= -8
Code: BECI
Step-by-step explanation:
To answer this you could do a couple things. 1. Actually calculate both tips and then subtract them. Here is the math ( assuming it is $60, not 60% that you mean). a. 0.15 x 60 = $9. b. 0.0825 x 2 x 60=$9.90. c. 9.90-9.00= $0.90 difference.
The other strategy would be to find the difference on the percents and then multiply by $60. a. 8.25%x2=16.5%-15%. Difference of 1.5%. b. 0.015 x $60=$0.90.
