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Lostsunrise [7]
3 years ago
12

I really need help with this. don't do this for the points, please.

Mathematics
1 answer:
nordsb [41]3 years ago
7 0

Answer:

4 months

Step-by-step explanation:

I first did 45 minus 125 then divided it by 20 because that how much he pays each month. So the answer has to be 4 months.

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3. Mrs Ofori-Atta's class will be planting a food garden. Here is the plan they have agreed on. a) What is the total area of the
Scorpion4ik [409]

Answer:

2200cm

Step-by-step explanation:

6 0
3 years ago
in a class there are 40 students. There are 10 more boys than girls in the class, Let x be the number of boys and y be the numbe
belka [17]
X = boys
y = girls

x + y = 40 (in a class there are 40 students)
x = y + 10 (t<span>here are 10 more boys than girls in the class</span>)
5 0
4 years ago
If SE = 7 and EG = 20 , then SG =
Rina8888 [55]
Try 13 and if it’s wrong im sorry
6 0
4 years ago
I have the answer, 2-(3/x+2)
Marat540 [252]

Start with the answer format we want, and work your way toward forming a single fraction like so

a + \frac{b}{x+2}\\\\a*1+\frac{b}{x+2}\\\\a*\frac{x+2}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)+b}{x+2}\\\\\frac{ax+2a+b}{x+2}\\\\\frac{ax+(2a+b)}{x+2}\\\\

Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.

Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.

So, 4+b = 1 leads to b = -3

Therefore, a = 2 and b = -3

------------------------------------------------

An alternative route:

\frac{2x+1}{x+2}\\\\\frac{2x+1+0}{x+2}\\\\\frac{2x+1+4-4}{x+2}\\\\\frac{(2x+4)+1-4}{x+2}\\\\\frac{2(x+2)-3}{x+2}\\\\\frac{2(x+2)}{x+2}+\frac{-3}{x+2}\\\\2-\frac{3}{x+2}\\\\

I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.

------------------------------------------------

Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.

3 0
3 years ago
Read 2 more answers
Question 3 Essay Worth 10 points)
wolverine [178]

Answer:

I tried but I couldn't figure it out sorry

8 0
3 years ago
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