Two sets (or three technically)
sets {2, 4, 6, 8, 10} & {8,9,10}
The probability of one of the above numbers because it is a union of those two vars/sets so numbers from either set go
{2, 4, 6, 8, 9, 10}
Thats 6 of the 10 numbers
6/10
.6
If i'm wrong, sorry, haven't done this kind of stuff in a while
So C= dxpi or rx2xpi= c in this case 7x 2 = 14 is diameter do E D and A finds the diameter and the rest do not
64,013,000 =
<span>six hundred and four hundred thirteen thousandths =
60,000,000 + 4,000,000+10,000+3,000</span>
I think I did this test and I think it’s A
