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3 years ago

A basketball team needs to raise $500 and there are 12 players how much money does each player need to raise

Mathematics

2 answers:

trasher [3.6K]3 years ago

7 0

Answer:

41.67 or About $42

Step-by-step explanation:

It would be $42 dollars because you first need to do 500 divided by 12 which equals 41.6666667. That being said it would make sense to round the number so that each player contributed enough. I rounded to 42 because any number 5 and above you round up. Because the number is 41.6, you round up to 42. Also, they could contribute $41.67 but most likely each player would contribute around $42. Hope this helps!

Grace [21]3 years ago

6 0

Answer:

$41.67

Step-by-step explanation:

Money that the team needs to raise $500

Players 12

Money ÷ Players = Money per player

500÷12=41.6666666666667

So... 41.67

Or if the question gave you description, follow that!

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a scuba diver, who was 25 2/3 feet beneath the surface of the water, descended 5 1/2 feet. from this depth, how many feet must t

Effectus [21]

Answer:

31 1/6 feet

Step-by-step explanation:

add 25 2/3 to 5 1/2 to see how far under the surface he is; use common denominator of 6

25 4/6 + 5 3/6 = 30 7/6

30 7/6 is the same as 30 + 1 1/6 so diver must ascend 31 1/6 feet

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3 years ago

Silas and Lilly attended a math conference. The total registration fee was $327.50. If each person paid the same amount, which e

castortr0y [4]

Answer:I think the answer is letter B.

Step-by-step explanation:

8 0

2 years ago

A fruit seller has 3 crates of apples. Each crate has 100 apples. If he packed 6 apples in 1 box. Which of these gives the numbe

xz_007 [3.2K]

Answer:

300 divided by 6

Step-by-step explanation:

Given that;

Number of crates of apple owned by fruit seller = 3 crates

Number of apples in each crate = 100 apples

He packed 6 apples in 1 box;

Unknown:

Number of boxes needed to pack all the apples = ?

This problem is pretty straight forward;

Number boxes needed to pack all apples = $\frac{Number of crates owned by fruit seller x number of apples per crate}{Number of apples per box}$

Input the parameters and solve;

Number of boxes need to pack all apples = $\frac{100 x 3}{6}$ = $\frac{300}{6}$

So the solution is 300 divided by 6

5 0

3 years ago

Pls help I’ll brainlest

Natali [406]

Answer:

C. 5.8 × $10^{-5}$

Step-by-step explanation:

0.000058

4 zeros

4 + 1 = 5

5.8 × 10⁻5

8 0

3 years ago

A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o

Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(X $E(X_{k}) = n_{k} * p_{k}$

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = $\frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}$

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= $\frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\$ = 0.00022

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= $\frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\$ = 0.000001

P(X₁≤2) = $\frac{22!}{0!} * 0.08^{0} * (0.92)^{22}$ + $\frac{22!}{1!} * 0.08^{1} * (0.92)^{21}$ + $\frac{22!}{2!} * 0.08^{2} * (0.92)^{20}$ = 0.7442

I hope you have a SUPER day!

8 0

3 years ago