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Delvig [45]
4 years ago
14

10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then

randomly selected. What is the probability of selecting two prime numbers?
A) 2/15
B) 4/18
C) 7/90
D) 1/10
Mathematics
1 answer:
katrin [286]4 years ago
4 0
The primes in the set [1,10] are 1,2,3,5,7 and the number of elements is 10 so

(5/10)(4/9)=20/90=2/9

which for some reason they converted to 4/18 :P
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kkurt [141]

Answer:

a) 1/24 do total

Step-by-step explanation:

We have that:

The total is 1.

The first friend gets 1/4 of the total.

The second friend gets 1/3 of the total

The third friend gets 3/8 of the total.

The remaining is x.

So

\frac{1}{4} + \frac{1}{3} + \frac{3}{8} + x = 1

The least common multiple between 4, 3 and 8 is 24. So

\frac{6 + 8 + 3*3 + 24x}{24} = 1

23 + 24x = 24

24x = 1

x = \frac{1}{24}

So the correct answer is:

a) 1/24 do total

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OlgaM077 [116]

Answer:

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Step-by-step explanation:

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Solve the proportion by cross- multiplying.

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Damm [24]
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dedylja [7]
Answer: 5/6

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jeka94

Answer:

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Step-by-step explanation:

Step 1: Subtract 11x from both sides.

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