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AleksandrR [38]
3 years ago
6

Help with all these plz!

Mathematics
1 answer:
spayn [35]3 years ago
4 0

Answer:

9    10     10   17   3

Step-by-step explanation:

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gene sold 10 glasses of lemonade while setting up his lemonade stand. after opening, he sold an average of20 glasses each hour.
Dovator [93]
Well we know that he sold 20 glasses every hour. if h is the number of hours he worked we know the expression would be 20h 
1 hr   = 20 glasses
2 hr = 40 glasses
3  hr  = 60 glasses   
Keep the pattern going to figure out which hour he got his 100th glass sold. 
6 0
3 years ago
What are the common multiples of 2 3 and 5
LUCKY_DIMON [66]
Los multiplos de 2 es 2,4 ,6,8,10,12,14, etc Del 3: 3,6,9,12,15,18,21,24,27,30,etc Del 5: 5,10,15,20,25,30,35,40,etc
3 0
3 years ago
Please help me on thiss
Hitman42 [59]

Answer:

-1.2

Step-by-step explanation:

3n + 5 = 1/2(11n + 16)

3n + 5 = 5.5n + 8

5 = 2.5n + 8

-3 = 2.5n

-3/2.5 = n

-1.2 = n

Hope this helps!

6 0
2 years ago
Read 2 more answers
Please find the answer and explain how you found it
Zigmanuir [339]
The answer is D I made a video incase you can’t see the picture well.
Message me if you want the video.

8 0
3 years ago
John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created
Over [174]

We will have that for the previous year, he had in the account:

m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106

For the year previous to that one, he had:

m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964

For the previous year to that, he had:

m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462

For the year previous to that one, he had:

m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314

For the second year that the money was in the account, there was:

m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775

And the orinial ammount of money that was in the account was:

m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669

From this, we know that Jhon had originally $1400.37 in the bank account.

6 0
11 months ago
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