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nadezda [96]
4 years ago
13

Round each factor to the nearest ten and estimate the product of 12(22)

Mathematics
1 answer:
Alex73 [517]4 years ago
3 0

Step-by-step explanation:

12 is rounded to 10

22 is rounded to 20

20×10= 200

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24-4x=2x<br> show your work, will mark brainliest
vladimir2022 [97]

Answer:

x=4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

24−4x=2x

24+−4x=2x

−4x+24=2x

Step 2: Subtract 2x from both sides.

−4x+24−2x=2x−2x

−6x+24=0

Step 3: Subtract 24 from both sides.

−6x+24−24=0−24

−6x=−24

Step 4: Divide both sides by -6.

−6x /−6  = −24 /−6

x=4

5 0
3 years ago
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Please help me branniest <br> Explain answers
Nana76 [90]

when a number is raised to two powers, the first step is to multiply the two powers together:

1/3 * 3 = 1

Now you have 5^1 which equals 5.


The answer is B. 5



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3 years ago
Sharon buys 14 folders for 0.75 dollars each how much change she will
AlekseyPX
0.75 x 14 = 10.50
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7 0
3 years ago
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

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3 years ago
What is the third quartile of this data set?
Lena [83]

Answer:

40 so C would be your answer.

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