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juin [17]
3 years ago
6

Out of 200 std in a class. 150 like math , 120 like nepali .if the number of std who like nepali only is one third of the std wh

olike math .find who lile both subjects​
Mathematics
1 answer:
hichkok12 [17]3 years ago
3 0

<u>ANSWER:  </u>

70 students like both nepali and maths.

<u>SOLUTION: </u>

Given,out of 200 students in a class. 150 like math, 120 like nepali.

The number of students who like nepali only is one third of the students who like math .

We need to find how many likes both subjects.

Let, the number of students who like only nepali be x.

Then, x is one-third of students who like maths.

x = \frac{1}{3} \times students who like maths

\begin{array}{l}{x=\frac{1}{3} \times 150} \\\\ {x=\frac{150}{3}} \\\\ {x=50}\end{array}

Now, out of 120 students who like nepali, only 50 students like nepali alone, which means remaining students like both nepali and maths

Students who like both subjects = 120 – 50 = 70.

Hence,70 students like both nepali and maths.

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muminat
<span> 0.8  that for the 44/55 idk what u want me to do with the 39

here how 2 turn them into decimals 
</span>

The fraction bar means "divided by." So finding the decimal equivalent of a fraction such as 1/4 means 1 divided by 4.
1 ÷ 4 = 0.25

It is not necessary to reduce a fraction before you convert it to a decimal but doing so might make the long division easier if you are doing it by hand.

For example, 9/12 = 9 ÷ 12 = 0.75. If you solve this with a calculator then it is easy to get the answer. However, if you use long division to solve this problem by hand or in your head, reducing 9/12 = 3/4, may make the problem easier. You may even recognize that 3/4 = 0.75 because 3 quarters equals 75 cents.



cited from -http://www.calculatorsoup.com/calculators/math/fraction-to-decimal-calculator.php

4 0
3 years ago
NEED ANSWERED ASAP WILL REWARD BRAINLIEST
Luda [366]

Answer:

The sum of the first 100 terms is 60400

Step-by-step explanation:

* Lets revise the arithmetic sequence

- There is a constant difference between each two consecutive

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- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….

# 5  ,  10  ,  15  ,  20  ,  …………………………

# 12  ,  10  ,  8  ,  6  ,  ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

 between each two consecutive terms n is the position of the

 number

- The sum of first n terms of an Arithmetic sequence is calculate from

 Sn = n/2[a + l], where a is the first term and l is the last term

* Now lets solve the problem

- We will use method (1)

- From the table the terms of the sequence are:

 10 , 22 , 34 , 46 , 58 , 82 , 94 , ............., where 10 is the first term

∵ an = a1 + (n - 1) d ⇒ explicit formula

∵ a1 = 10 and a2 = 22

∵ d = a2 - a1

∴ d = 22 - 10 = 12

- The 100th term means the term of n = 100

∴ a100 = 10 + (100 - 1) 12

∴ a100 = 10 + 99 × 12 = 10 + 1188 = 1198

∴ The 100th term is 1198

- Lets find the sum of the first 100 terms of the sequence

∵ Sn = n/2[a1 + an]

∵ n = 100 , a = 10 , a100 = 1198

∴ S100 = 100/2[10 + 1198] = 50[1208] = 60400

* The sum of the first 100 terms is 60400

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Given

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We have two more visible full squares, which we can add on to our 16, putting it at 18. But that half squares, we have 4 total have squares. We know that 1/2 + 1/2 = 1

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