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alekssr [168]
3 years ago
6

What is the midpoint of the segment shown below? (-4,6) (4,-2)

Mathematics
2 answers:
natulia [17]3 years ago
7 0

Answer:

math-way is a website where you can ask it math questions and it gives you the correct answer in seconds

Step-by-step explanation:

Marina CMI [18]3 years ago
5 0

See picture for math work and answer.

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For what values of x is f(x) = square root of x-4 equal to 4?
zaharov [31]

Answer:

x = 20

Step-by-step explanation:

given f(x) = \sqrt{x-4}, we have to solve

\sqrt{x-4} = 4

Square both sides

(\sqrt{x-4})² = 4²

x - 4 = 16 ( add 4 to both sides )

x = 20

As a check

\sqrt{20-4} = \sqrt{16} = 4 ← correct




3 0
4 years ago
Let f (x)=1/x and g (x)=x^2+5x. A. Find (f×g)(x). B. Find the domain and range of (f×g)(x).
Ira Lisetskai [31]

we are given

f(x)=\frac{1}{x}

g(x)=x^2+5x

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

(fXg)(x)=\frac{1}{x} (x^2+5x)

we can simplify it

(fXg)(x)=\frac{1}{x} (x(x+5))

(fXg)(x)=x+5

(B)

Domain:

Firstly, we will find domain  of f(x) , g(x) and (fxg)(x)

and then we can find common domain

Domain of f(x):

f(x)=\frac{1}{x}

we know that f(x) is undefined at x=0

so, domain will be

(-\infty,0)∪(0,\infty)

Domain of g(x):

g(x)=x^2+5x

Since, it is polynomial

so, it is defined for all real values of x

now, we can find common domain

so, domain will be

(-\infty,0)∪(0,\infty)..............Answer

Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

Range of f(x):

f(x)=\frac{1}{x}

we know that range is all possible values of y for which x is defined

since, horizontal asymptote will be at y=0

so, range is

(-\infty,0)∪(0,\infty)

Range of g(x):

g(x)=x^2+5x

Since, it is quadratic equation

so, its range will be

[-6.25,\infty)

now, we can find common range

so, range will be

(-6.25,0)∪(0,\infty).............Answer

6 0
3 years ago
PLEASE HELP ME thank you<br><br> answer needs to be in simplest radical form <br><br> find d
sweet [91]

Answer:

d=10

Step-by-step explanation:

Pythagorean theorem:

d^2+d^2=10\sqrt{2}^2,\\2d^2=200,\\d^2=100,\\d=\boxed{10}

Alternative:

\cos 45^{\circ}=\frac{d}{10\sqrt{2}},\\\frac{\sqrt{2}}{2}=\frac{d}{10\sqrt{2}},\\2d=10\sqrt{2}\cdot \sqrt{2},\\2d=20,\\d=\boxed{10}

Alternative (derived from the Pythagorean theorem):

All 45-45-90 triangles have side lengths x-x-x\sqrt{2}, where x\sqrt{2} is the hypotenuse. Since this triangle's hypotenuse is 10\sqrt{2}, its sides are 10-10-10\sqrt{2}.

3 0
3 years ago
Read 2 more answers
What is the value of x? <br><br> Enter your answer in the box. <br><br> X =
agasfer [191]
102 ok i just have to write
8 0
3 years ago
CAN YOU GUYS HELP MY SISTER OUT FOR POINTS AND BRINLESET?!?!?!?
Pani-rosa [81]

Answer:

1. 1/6

2. 1/9

3. 1/10

4.it would still be 9/10

-----------------------------------------------------------------------------------------------------------------

I cant answer that one sorry

-----------------------------------------------------------------------------------------------------------------

4 (im a little less confident in  this one :( )

-----------------------------------------------------------------------------------------------------------------

1/4

4 0
4 years ago
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