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kondor19780726 [428]
3 years ago
12

Which algebraic rule describes the 180° counter-clockwise rotation about the origin?

Mathematics
2 answers:
Hoochie [10]3 years ago
7 0

Answer:  C) (x, y) → (−x, −y)

Step-by-step explanation:

When we rotate a figure 180°clockwise or counter-clockwise , the magnitude of x and y coordinates remains same but their signs got changed.

For example : After a rotation of 180°clockwise or counter-clockwise (3,4) becomes (-3,-4).

Algebraically , we can say

Ordered pair (x , y ) will become (-x, -y) after a rotation of 180°clockwise or counter-clockwise.

Thus , the algebraic rule describes the 180° counter-clockwise rotation about the origin will be :-

C) (x, y) → (−x, −y)

Nikolay [14]3 years ago
5 0

Answer:

C

Step-by-step explanation:

Under a counterclockwise rotation about the origin of 180°

a point (x, y ) → (- x, - y) → C

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What is the probability that no 1s will be in the output for an input sequence of 10 digits??
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4 years ago
Determine whether the series is arithmetic or geometric. Then evaluate the finite series for the specified number of terms. 10 +
Salsk061 [2.6K]

Answer:

10 + 7 + 4 + . . .; n = 5​

The series is arithmetic

Common difference between terms = (-3)

10 - 3 = 7

7 - 3 = 4

Or:

10 + (-3) = 7

7 + (-3) = 4

--------------------------------------------------------------------------

<u>Another example</u>:

Arithmetic:

5, 9, 13, 17

common difference = 4

5 + 4 = 9

9 + 4 = 13

Geometric:

4, 8, 16, 32

4 × 2 = 8

8 × 2 = 16

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--------------------------------------------------------------------------

10 + 7 + 4 + . . .; n = 5​

a₁ = 10

a₂ = 7

a₄ = a₃ + d = 4 + (-3) = 4 - 3 = 1     (d = common difference)

a₅ = a₄ - 3 = 1 - 3 = -2

Or with formula:

d=a_{n} -a_{n-1}

d = a₂ - a₁ = 7 - 10 = -3

aₙ = a₁ + (n - 1)d

fourth term = a₄ = 10 + (4 - 1)(-3) = 10 + 3(-3) = 10 + (-9) = 10 - 9 = 1

fifth term = a₅ = 10 + (5 - 1)(-3) = 10 + 4(-3) = 10 + (-12) = 10 - 12 = -2

Sum of the finite series (if n = 5):

S_{n} =\frac{n(a_{1} +a_{n} )}{2} \\S_{5} =\frac{5(a_{1} +a_{5} )}{2} \\S_{5} =\frac{5(10 +(-2) )}{2} \\S_{5} =\frac{5(8 )}{2} =\frac{40}{2} =20

Manual count: S₅ = 10 + 7 + 4 + 1 + (-2) = 20

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Answer:

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