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shutvik [7]
3 years ago
13

The image of a dust mite from a scanning electron microscope is 1.5×10 to the 2nd millimeters wide. The image is 5×10 to 2nd tim

es life size. How many millimeters wide is the dust mite?
Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0
600 millimeters is the accuracy
Schach [20]3 years ago
3 0

Given that The image of a dust mite from a scanning electron microscope is 1.5 \times 10^2 millimetres wide. And that image is 5 \times  10^2 times life size. Now we have to find how many millimetres wide is the dust mite. To find that we just need to divide the the width of dust mite by the scale value of microscope. I mean divide 1.5 \times10^2 millimetre by 5 \times 10^2

So the answer is given by

Width of the dust mite =\frac{1.5 \times 10^2}{5 \times 10^2} =\frac{1.5 }{5 } =0.3

Hence final answer is 0.3 milimetre.



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12.10 rounding to the nearest 10th
Sedaia [141]

Answer:

12

Step-by-step explanation:

Your answer is 12. I hope this helps!!!

6 0
2 years ago
When QS=6x and CS=5x-8, what is AB?
patriot [66]

Answer:

AB = x+ 8

Step-by-step explanation:

Given : QS=6x and CS=5x-8

From the given figure,

QS = QC + CS

We are given with  QS  and CS

Replace it the above equation

6x = QC + 5x -8

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Subtract 5x on both sides

x = QC + -8

Add 8 on both sodes

QC= x + 8

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4 0
3 years ago
After a 20% price reduction, a cordless phone sold for $48. What was the phones price before the reduction?
GalinKa [24]
After 20% reduction the price is $48 which means $48 is only 80% of the original price...so let x= original price 
<span>48=.8x </span>
<span>60=x </span>
<span>it was $60

</span>
6 0
3 years ago
The coordinate grid shows a pentagon. The pentagon is translated 4 units to the left and 9 units down to create a new pentagon.
Harrizon [31]
(X-4, y-9) since it moves left its negative and the y went down makes that negative too
7 0
2 years ago
Mr. Akika has 49 21 cent and 31 cent stamps all told. The stamps are worth $13.39. how many of each kind of stamps does he have?
Lana71 [14]

Mr Akika has 18  21-cent stamp and 31 31-cent stamp.  

He has 49 21-cent and 31-cent stamps all told.

let

x = number of 21 cent stamp

y = number of 31 cent stamp

Therefore,

<h3>Total number of stamp:</h3>
  • x + y  = 49
<h3>Total cost of stamp:</h3>
  • 21x + 31y = 1339

Therefore,

x + y = 49

21x + 31y = 1339

21x + 21y = 1029

10y = 310

y = 310 / 10

y = 31

Therefore,

x = 49 - 31

x = 18

Therefore, Mr Akika has 18  21-cent stamp and 31 31-cent stamp.  

learn more on system of equation: brainly.com/question/1369852?referrer=searchResults

4 0
2 years ago
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