Write two equivalent fractions for 5/10

2 answers:

7 0

1/2 and 10/20

to get 1/2 you have to divide 5/10 by 5:

5 / 5 1
----- = -----
10 / 5 2

to get 10/20 you have to multiply 5/10 by 2:

5 * 2 10
----- = ----
10 * 2 20

Hope it helps! =)

Alisiya [41]3 years ago

4 0

1/2, 3/6. As 5 is one half of ten, it would be equivalent to 1/2. Since it is equivalent to one half, 3/6 would also be equivalent, as 3 is one half of 6. I hope this helps!

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find the measure of the arc or angle indicated. assume that lines which appear tangent are tangent

Serjik [45]

Answer:

Option (1)

Step-by-step explanation:

By the property of alternate segment theorem,

"Angle formed between the tangent and the chord in a circle measures the half of the measure of the intercepted arc"

m(∠EFG) = $\frac{1}{2}$ × m(minor arc FG)

minor arc FG = 2m(∠EFG)

= 2(76°)

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Therefore, Option (1) will be the correct option.

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3 years ago

Determine the quotient, q(x), and remainder, r(x) when

Vinvika [58]

ANSWER

Quotient:

$q(x) = 4 {x}^{2} + 3x + 2$

Remainder:

$r(x) = 3x + 1$

EXPLANATION

The given functions are

$f(x) = 12 {x}^{4} + 21 {x}^{3} + 31 {x}^{2} + 21x + 9$

and

$g(x) = 3 {x}^{2} + 3x + 4$

We want to find the remainder and quotient when f(x) is divided by g(x).

We perform the long division as shown in the attachment.

The quotient is

$q(x) = 4 {x}^{2} + 3x + 2$

The remainder is

$r(x) = 3x + 1$

5 0

3 years ago

Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$