The correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>. (Correct choice: H)
<h3>How to analyze a second orden polynomial with constant coefficients</h3>
In this case we have a second order polynomial of the form <em>x² - (r₁ + r₂) · x + r₁ · r₂</em>, whose solution is <em>(x - r₁) · (x - r₂)</em> and where <em>r₁</em> and <em>r₂</em> are the roots of the polynomial, which can be real or complex numbers but never both according the fundamental theorem of algebra.
If we know that <em>g(x) =</em> <em>x² -</em> 6 <em>· x -</em> 16, then the <em>factored</em> form of the expression is <em>g(x) = (x - </em>8<em>) · (x + </em>2<em>)</em>. Hence, the correct choice of this question with the given polynomial is <em>"The zeros are </em>-2<em> and </em>8<em>, because the factors of g are (x + </em>2<em>) and (x - </em>8<em>)"</em>. 
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Answer:
45%
Step-by-step explanation:
9/20. 20* 5= 100. 9*5=45. 45/100=45%
Answer:
4096π / 5
Step-by-step explanation:
∫∫∫ (x² + y² + z²) dV
In spherical coordinates, x² + y² + z² = r², and dV = r² sin φ dr dθ dφ.
E is the range 0 ≤ r ≤ 4, 0 ≤ φ ≤ π, 0 ≤ θ ≤ 2π.
∫₀ᵖⁱ∫₀²ᵖⁱ∫₀⁴ (r²) (r² sin φ dr dθ dφ)
∫₀ᵖⁱ∫₀²ᵖⁱ∫₀⁴ (r⁴ sin φ) dr dθ dφ
Evaluate the first integral.
∫₀ᵖⁱ∫₀²ᵖⁱ (⅕ r⁵ sin φ)|₀⁴ dθ dφ
∫₀ᵖⁱ∫₀²ᵖⁱ (¹⁰²⁴/₅ sin φ) dθ dφ
¹⁰²⁴/₅ ∫₀ᵖⁱ∫₀²ᵖⁱ (sin φ) dθ dφ
Evaluate the second integral.
¹⁰²⁴/₅ ∫₀ᵖⁱ (θ sin φ)|₀²ᵖⁱ dφ
¹⁰²⁴/₅ ∫₀ᵖⁱ (2π sin φ) dφ
²⁰⁴⁸/₅ π ∫₀ᵖⁱ sin φ dφ
Evaluate the third integral.
²⁰⁴⁸/₅ π (-cos φ)|₀ᵖⁱ
²⁰⁴⁸/₅ π (-cos π + cos 0)
²⁰⁴⁸/₅ π (1 + 1)
⁴⁰⁹⁶/₅ π
I believe it will be at 10:10 because the least common multiple of 10 and 12 is 60 therefore you add 60 minutes to 9:10.
Answer:
Therefore 
and 
are fundamental solution of the given differential equation.
Therefore and are linearly independent, since 
The general solution of the differential equation is
Step-by-step explanation:
Given differential equation is
y''-y'-20y =0
Here P(x)= -1, Q(x)= -20 and R(x)=0
Let trial solution be 
Then, 
and 
Therefore the complementary function is = 
Therefore and are fundamental solution of the given differential equation.
If 
and 
are the fundamental solution of differential equation, then
Then and are linearly independent.
Therefore and are linearly independent, since
Let the the particular solution of the differential equation is
and
Here 
, 
,
,and 
=0
and
=0
The the P.I = 0
The general solution of the differential equation is
