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kakasveta [241]
2 years ago
15

A hot air balloon rose from a height of 100 m to 400 m in 3 minutes. What was the balloon’s rate of change?

Mathematics
1 answer:
maria [59]2 years ago
7 0

Answer:

1.666666667 meter per sec^2

Step-by-step explanation:

I feel like this is physic

using acceleration formla Vf-Vi/t

so 400-100/180sec

300/180

1.666666667 meter per sec^2

Hey  im still learning tell me if you feel like im wrong OwO

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Brrunno [24]

Answer:

the correct answer to your question would be option c

4 0
2 years ago
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Solve for w -2/5+1/2w= -6/7
I am Lyosha [343]
-2/5 +1/2w = -6/7
move the -2/5 over by addition

1/2w = -16/35
w = -32/35
8 0
2 years ago
The greatest common factor(GCF) of LaTeX: x^7,\:x^3,\:x^5\:is\:_{ }__________.
wolverine [178]

Answer:

<h3>x^3</h3>

Step-by-step explanation:

We are to find the greatest common factor of x^7, x^3 and x^5

x^7 = x^3 * x^4

x^3 = x^3 * 1

x^5 = x^3 * x^2

From both factors, we cam see that x^3 is common to the three, hence the GCF is x^3

7 0
2 years ago
Which of the following is the third term of the expansion (a + b)^n ?
Luba_88 [7]

Answer:

  C(n, 2)a^(n-2)b^2

Step-by-step explanation:

Generally, the expansion is written in decreasing powers of "a", so the first few terms would have variable constellations that look like ...

  a^n, a^(n-1)b, a^(n-2)b^2, ...

The coefficients would be (in order), C(n, k) for k increasing from 0, so the coefficient of the 3rd term would be C(n, 2).

5 0
3 years ago
Levi invested $5,300 in an account paying an interest rate of 2.4% compounded daily. Assuming no deposits or withdrawals are mad
suter [353]

Answer: $6,120.86

Step-by-step explanation:

Formula to calculate the accumulated amount in n years (compounded daily)  is given by :-

A=P(1+\dfrac{r}{365})^{365\times n}

P= Initial amount

r= Rate of interest ( in decimal)

As per given , we ahve

P= $5300

r= 2.4%=0.024

n= 6 years

Put these values in formula , we get

A=5300(1+\dfrac{0.024}{365})^{365\times6}\\\Rightarrow\ A=5300(1.00006575342)^{2190}\\\Rightarrow\ A=6120.85673631\approx6120.86

Hence, there would be $6,120.86 in the account after 6 years.

5 0
3 years ago
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