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White raven [17]
3 years ago
6

Write each of the following numerals in base 10. For base​ twelve, T and E represent the face values ten and​ eleven, respective

ly.
233five

11000two

43Etwelve
Mathematics
1 answer:
kifflom [539]3 years ago
5 0
233 base five = 2 x 5^2 + 3 x 5 + 3 x 1 = 2 x 25 + 15 + 3 = 50 + 18 = 68 base 10

11000 base two = 1 x 2^4 + 1 x 2^3 = 16 + 8 = 24 base ten

43E base twelve = 4 x 12^2 + 3 x 12 + 11 x 1 = 4 x 144 + 36 + 11 = 576 + 47 = 623 base ten
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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Help me pleaseeee xo
dolphi86 [110]

Answer:

12

Step-by-step explanation:

4 0
3 years ago
Can you pls help me with this?☺️<br>thank you ☺️<br>​
den301095 [7]

12. MORT

13. MNR

14. SDT

15. MOSR

4 0
3 years ago
Evaluate the piecewise function for the given values.
adoni [48]

Answer:

f(-3) = -2

f(-2.6) = -2

f(0.6) = 2.4

f(4.5) = 8.5

Step-by-step explanation:

(Whole question:

Evaluate the piecewise function for the given values.

Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)

As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.

So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2

For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2

For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4

For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5

5 0
2 years ago
Opening Exercise
Jobisdone [24]

Answer:

100% of 180 = 180

25% of 180 = 45

-75% of 180 = -135

37.5% of 180 = 67.5

Step-by-step explanation:

I looked them up on an app so I hope its right!

4 0
2 years ago
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