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Solnce55 [7]
4 years ago
11

Find the slope of the line containing the points (3,-2) and (-1,6)​

Mathematics
2 answers:
Hatshy [7]4 years ago
4 0
Of poopp chunkyh rudntp ejid
dezoksy [38]4 years ago
3 0

Answer: the answer is -2

Step-by-step explanation: use slope formula

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The bottom of a rectangular swimming pool has an area of 150 square meters and a perimeter of 50 meters. What are the dimensions
AysviL [449]

The  dimensions of the pool is 15m by10m

<h3>Area and perimeter of rectangle</h3>

A pool is rectangular in nature. If a rectangular swimming pool has an area of 150 square meters and a perimeter of 50 meters, then;

lw = 150

2(l+w) = 50

l + w = 25

where

l is the length

w is the width

From the equation 3

l = 25 - w

Substitute into 1

(25-w)w = 150
25w-w² = 150
w²-25w+150 = 0
w²-10w-15w+150 = 0

Factor

w(w-10)-15(w-10) = 0

w = 10 and 15

l = 150/10 = 15

Hence the  dimensions of the pool is 15m by10m

Learn more on dimension here: brainly.com/question/26740257

#SPJ1

7 0
1 year ago
Need help ASAP thank u
Ivahew [28]

Answer:

21

Step-by-step explanation:

Because...

6 0
3 years ago
Cans 6 cm 3 cm and 9 cm make a triangle
Alja [10]

Answer:

Step-by-step explanation:

No it’s makes more than it so no

3 0
3 years ago
Read 2 more answers
ANSWER ASAP (17 points)
elixir [45]

Answer:

A.) x > 50

Step-by-step explanation:

hopefully my answer helps! ♡

(if my answers helped you please tell me, therefore I know.. that I did them correctly or incorrectly. anyways, have a great day/night!)

3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
ycow [4]

Answer: 0) 0.22

              1) 0.20

              2) 0.12

              3) 0.14

              4) 0.28

              5) 0.04

<u>Step-by-step explanation:</u>

The total frequency is 33+30+18+21+42+6 = 150.  This means they ran the experiment 150 times.  The probability (P) is calculated by the satisfactory number of outcomes (frequency) divided by the total number of experiments/outcomes (total frequency):

\begin{array}{c|c||lc}\underline{x}&\underline{f}&\underline{f\div 150}&\underline{\text{P}}\\0&33&33\div 150=&0.22\\1&30&30\div150=&0.20\\2&18&18\div 150=&0.12\\3&21&21\div 150=&0.14\\4&42&42\div 150=&0.28\\5&6&6\div 150=&0.04\end{array}\right]

5 0
3 years ago
Read 2 more answers
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