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3 years ago

8

Terry has 12 candles. She needs 250 for a wedding event and they come in boxes of 12. What is the minimum number of boxes she ne

eds to buy to have enough for the event?

1 answer:

AfilCa [17]3 years ago

6 0

Answer:

minimun number is 20

Step-by-step explanation:

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For a school fundraiser, Mai will make school spirit bracelets. She will order bead wiring and alphabet beads to create the scho

Ket [755]

Answer: Total number of bracelet: 235

Step-by-step explanation:

Given:

Total budget= $1,500

Spend on wire = $250

Per braclet beads = $5.30

Find:

Total number of bracelet

Computation:

Total number of bracelet = [1,500 - 250]

Total number of bracelet = [1,250/ 5.30

Total number of bracelet = 235.849

Total number of bracelet = 235 [By round minium]

8 0

3 years ago

I NEED THIS ASAP please. can someone please answer this question i put the picture its on Simplify Expressions im giving 15 poin

kakasveta [241]

Answer:

in step 4

Step-by-step explanation:

we have

$0.5(-12c+6)-3(c+4)+10(c-5)\\\\step1=-12c(0.5)+6(0.5)-3(c+4)+10(c-5)\\\\=-6c+3-3(c+4)+10(c-5)\\\\$

so step 1 is correct

step 2

$-6c+3-3(c+4)+10(c-5)\\\\=-6c+3+c(-3)+4(-3)+10(c-5)\\\\=-6c+3-3c-12+10(c-5)$

so step 2 is correct

step 3

$-6c+3-3c-12+10(c-5)\\\\=-6c+3-3c-12+c(10)-5(10)\\\\=-6c+3-3c-12+10c-50$

so step 3 is correct

step 4

$-6c+3-3c-12+10c-50\\\\=(-6c-3c+10c)+(3-12-50)\\\\=(-6-3+10)c+(-9-50)\\\\=(-9+10)c-59\\\\=c-59$

so step 4 is incorrect

5 0

4 years ago

Find Each Sum.<br> (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =

tia_tia [17]

To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.

<span>(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c</span>² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d

6 0

3 years ago

Lelechka [254]

Answer:

$695.88

Step-by-step explanation:

579 + 32 = 611

8% of 611 = 48.88

611 + 48.88 = 659.88

Stay safe! <3

6 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

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