How can I solve this equation X-5=0.1(x+5)
2 answers:
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Answer:
.
Step-by-step explanation:
We have been given that a variable force of pounds moves an object along a straight line when it is x feet from the origin. We are asked to find the work done in moving the object from x = 1 ft to x = 10 ft.
We know that , where F represents force.
Now, we will integrate both sides of equation as:
Take the constant out:
Upon applying power rule of integrals, we will get:
Therefore, the work done by the object is .
Answer:
(- 2, 15 ) and (2, 7 )
Step-by-step explanation:
Given the 2 equations
y = 3x² - 2x - 1 → (1)
2x + y = 11 → (2) ← subtract 2x from both sides
y = 11 - 2x → (3)
Substitute y = 3x² - 2x - 1 into (3)
3x² - 2x - 1 = 11 - 2x ( subtract 11 - 2x from both sides )
3x² - 12 = 0 ( add 12 to both sides )
3x² = 12 ( divide both sides by 3 )
x² = 4 ( take the square root of both sides )
x = ± = ± 2
Substitute these values into (3) for corresponding values of y
x = - 2 : y = 11 - 2(- 2) = 11 + 4 = 15 ⇒ (- 2, 15 )
x = 2 : y = 11 - 2(2) = 11 - 4 = 7 ⇒ (2, 7 )
Volume is a three-dimensional scalar quantity. The volume of the space between the cylinder and the two cones is 1184.43183 cm³.
<h3>What is volume?</h3>A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given the circumference of the base is 61 cm, therefore, the radius of the base will be,
Circumference = 61 cm
2πR = 61
R = 61/(2π) = 9.70845 cm
The volume of the cylinder(Outside shell) can be written as,
Volume = πR²×H
= π× (9.70845)² ×12
= 3553.29326 cm³
The volume of the two identical cones will be,
The volume of the cone = 2× (1/3) × π × R² × H
= (2/3)×π×(9.70845²)×12
= 2368.86143 cm³
The volume of the space between the cylinder and the two cones is,
The volume between space = 3553.29326 cm³ - 2368.86143 cm³
= 1184.43183 cm³
Hence, the volume of the space between the cylinder and the two cones is 1184.43183 cm³.
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