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ololo11 [35]
3 years ago
11

Micah walks on a treadmill at 4 miles per hour. He has walked 2 miles

Mathematics
1 answer:
lana66690 [7]3 years ago
6 0
<span>Let time taken by Luke to cover the distance = x hours Speed of Luke = 6 miles per hour Therefore, Distance covered by Luke = 6x ------(1) Speed of Micah = 4 miles per hour Since Micah walked 2 miles before Luke started running, Luke started 1/2 an hour after Micah started. Therefore time taken by Micah to cover the distance = x+1/2 Distance covered by Micah = 4(x + 1/2) -------(2) Equating (1) and (2) 6x = 4(x+1/2) 6x = 4x +2 2x = 2 x= 1 Therefore Luke would take 1 hour to cover the distance covered by Micah.</span>
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Answer:

We conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

Step-by-step explanation:

Given the expression

25a^2-0.01b^{10}

Rewrite 25a^2-0.01b^{10} as \left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

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25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

Apply difference of two squares formulas:

x^2-y^2=\left(x+y\right)\left(x-y\right)

so

\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)

                               =\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)    ∵ \sqrt{0.01}=0.1,

Therefore, we conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

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