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Natasha2012 [34]
3 years ago
14

What is the radius of a circle that has circumference of 81pi square inches?

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0
I think the answer is 18 in

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Let T : V → W be a linear transformation from vector space V into vector space W.
wel

Explanation:

Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that

a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.

Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.

7 0
3 years ago
What is -2(-y) in expanded form ​
damaskus [11]

Answer:

2y

Step-by-step explanation:

(-2)(-y) = (-1)(2)(-1)(y) = (-1)^2\ccdot  2y = 2y

4 0
2 years ago
The diameter of a sphere is 21.6 cm. What is the sphere's volume? Round to the nearest tenth, if necessary.
NeX [460]
By definition, the volume of a sphere is:
 V =  \frac{4}{3}  (\pi) (r ^ 3)

 Where,
 r: sphere radio
 Substituting values we have:
 V =  \frac{4}{3}(3.14)(( \frac{21.6}{2} ) ^ 3)

 V = 5273.99424
 Rounding the result to the nearest tenth:
 V = 5274.0 cm ^ 3
 Answer:
 the sphere's volume is:
 V = 5274.0 cm ^ 3
5 0
3 years ago
What is $96 spent in 4 hours written as a unit rate in minutes​
lara31 [8.8K]

Answer: The unit rate of $96 spent in 4 hours is, $24 per hour.

Step-by-step explanation: To find the unit rate, you will need to write the information as a ratio, $96/4 hours. If you divide 96 by 4 you will get 24. That means this person spends $24 every hour or $24 per hour or $24/1 hour.

3 0
3 years ago
How do you rearrange formulae???
Romashka-Z-Leto [24]

Answer:

  make use of the properties of equality of of inverse functions and operations

Step-by-step explanation:

In algebra, each of the operations and functions we study has an inverse. As a rule, in any "solve for ..." situation, you want to "undo" the operations and functions performed on the variable of interest. You can use the Order of Operations to determine the order those operations are performed, then <em>undo them in reverse order</em>.

<u>Trivial example</u>:

  Solve x + 3 = 5 for x. We observe that the variable x has had 3 added to it. We "undo" the addition of 3 by adding its opposite, -3. The properties of equality require that we add this value to both sides of the equation:

  x +3 -3 = 5 -3

  x = 2 . . . . . after simplification

__

Rearranging also involves combining terms, finding a common denominator, rationalizing denominators, and similar algebraic operations. These sorts of operations are performed on variables and expressions in virtually the same way they are performed on numbers.

<u>Less trivial example</u>:

Suppose we have the equation of a circle, and we want to rearrange it to find an expression for y.

  (x -h)^2 +(y -k)^2 = r^2

We observe that y has k subtracted, the result is squared, and an x-term is added. Undoing these in reverse order means we first subtract the x-term, then take the square root, and finally add k.

  (y -k)^2 = r^2 -(x -h)^2 . . . . . . we subtracted the x-term from both sides

  y -k = √(r^2 -(x -h)^2) . . . . . . and took the square root. Notice we have retained only the positive square root, so the bottom half of the circle will go missing from our final equation.

  y = k + √(r^2 -(x -h)^2) . . . . . finally, we added k

This is the formula for a circle rearranged to find y in terms of x. The value of y is that associated with the top half of the circle. If we want the bottom half, we must negate the square root:

  y = k - √(r^2 -(x -h)^2) . . . . . . formula rearranged to give the bottom half

Note that the root function is used to "undo" the operation of raising to a power. As we said, each of the operations we study in algebra has its "undo". It is useful to pay attention to the inverse operation associated with any new operation or function you learn about. (trig functions, log functions, exponentiation come to mind)

3 0
3 years ago
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