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4 years ago

Graph the equation x-4y=2

1 answer:

8 0

<u><em>Go to google and google it and then go to Math and it will explain it to you. It will also show you how to get the answer.</em></u>

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Hey can you please help me posted picture of question :)

andriy [413]

The answer is the answer is C and F.

This is found by inserting the equation above into the quadratic formula or -b plus or minus the square root of b^2 - 4ac over 2a.

With that, you find that the first number is a -3, which eliminates choices B and D.

Then, solving the 4ac portion, you find that inside the square root the number is 29, which gives you the last two answer choices.

Hope this helps!

5 0

3 years ago

Respuesta de (-0.5)²

Vladimir79 [104]

Answer:

0.25

Step-by-step explanation:

we have

$(-0.5)^2$

we know that

$-0.5=-\frac{1}{2}$

substitute

$(-\frac{1}{2})^2=(-\frac{1}{2})(-\frac{1}{2})$

Remember that

$(-1)(-1)=1\\(-1)(1)=(-1)$

$(-\frac{1}{2})(-\frac{1}{2})=\frac{1}{4}=0.25$

5 0

3 years ago

After allowing 20percent discount and levying 13percent vat the value of a watch will be rs 904 what is the marked price of watc

Eddi Din [679]

9514 1404 393

Answer:

₹1000

Step-by-step explanation:

Let m represent the marked price. After the discount, the price is 0.80m. After the tax is added, the price is (0.80m)(1.13). This value is Rs 904, so the marked price is ...

(0.80m)(1.3) = ₹904

m = ₹904/(0.80×1.13) = ₹904/0.904

m ≈ ₹1000

The marked price of the watch is ₹1000.

5 0

3 years ago

Brooke had 70 chairs but he had less than20 rows how many chair he can put on each row

RideAnS [48]

Put in a equality

20 > (70/x)

then you solve

20x > 70

x>70/20

x> 3.5 you can not put part of a chair in a row so you round up

****You can put 4 or more chairs in a row****

4 0

3 years ago

Read 2 more answers

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

3 years ago