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Leni [432]
3 years ago
13

What is the factorization of 3x2 – 8x + 5?

Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0

Answer:

(x-1)(3x-5)

Step-by-step explanation:

3x^2 - 8x + 5

To factor it we use AC or splitting the middle term method

product is 3 times 5 is 15

Sum is -8

-3 times -5 is 15

-3 plus -5 is -8

Factors are -3 and -5

3x^2 -5x-3x+ 5

Group first two terms and last two terms

(3x^2 -5x)+(-3x+ 5)

x(3x-5)-1(3x- 5)

Factor out 3x-5

(x-1)(3x-5)

Charra [1.4K]3 years ago
3 0
3x2-8x+5
=6-8x+5
=6-3x-5x+5
=3(2-x)-5(x-1)
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8x2 − 5 + 7x4 − 9x − x5
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Answer:

=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

Step-by-step explanation:

Factor out comon Term -1

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Factor x^5-7x^4-8x^2+9x+5:\quad \left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)

x^5-7x^4-8x^2+9x+5

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a_0=5,\:\quad a_n=1

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Therefore, check the following rational numbers: ±\frac{1,\:5}{1}

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=\left(x-1\right)\frac{x^5-7x^4-8x^2+9x+5}{x-1}

\frac{x^5-7x^4-8x^2+9x+5}{x-1}=x^4-6x^3-6x^2-14x-5

=x^4-6x^3-6x^2-14x-5

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Answer:

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