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Leni [432]
3 years ago
13

What is the factorization of 3x2 – 8x + 5?

Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0

Answer:

(x-1)(3x-5)

Step-by-step explanation:

3x^2 - 8x + 5

To factor it we use AC or splitting the middle term method

product is 3 times 5 is 15

Sum is -8

-3 times -5 is 15

-3 plus -5 is -8

Factors are -3 and -5

3x^2 -5x-3x+ 5

Group first two terms and last two terms

(3x^2 -5x)+(-3x+ 5)

x(3x-5)-1(3x- 5)

Factor out 3x-5

(x-1)(3x-5)

Charra [1.4K]3 years ago
3 0
3x2-8x+5
=6-8x+5
=6-3x-5x+5
=3(2-x)-5(x-1)
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In your own words explain how you would solve this two step equation for the variable x. 9x-7=-7
NeX [460]

Answer:

Add 7 to both sides

Step-by-step explanation:

The equation has to be just x = y

There cannot be another number on the same side as the variable

Now that we did that, the equation is 9x = 0

x = 0

Well, that was easy lol

6 0
3 years ago
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Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

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2 years ago
Solve the system of equations y = 2x + 3 and 4x - 2y = -6 using a graphical method.
emmasim [6.3K]

Answer:

-1

Step-by-step explanation:

You are asked to solve this set by substitution. Note that the first equation defines

the value of y in terms of x. Therefore, you can use the right side of this equation

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in the second equation, the result is:

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2x + 3 = 4x + 7

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Let's set the goal of getting all the terms that contain x isolated on the left side of

the equal sign and all the constants by themselves on the right side. Begin by getting rid

of the +3 on the left side by subtracting 3 from the left side. But if you subtract

3 from the left side you must also subtract 3 from the right side. These subtractions

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Combining numbers on the left side and on the right side simplifies the equation to:

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2x = 4x + 4

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Now, in a similar fashion, let's get rid of the 4x on the right side by subtracting

4x from the right side. When we do this subtraction, to keep the equation in balance

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2x - 4x = 4x - 4x + 4

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On both sides of the equation combine terms containing x to get:

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-2x = 4

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Finally, solve for x by dividing both sides of the equation by -2 because -2 is the multiplier

of x. This results in:

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x = 4/-2 = -2

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So now that we know x = -2, we can return to either one of the original equations  

in the equation set and substitute -2 for x. Then we can solve for y. Let's return

to the first equation and substitute -2 for x. This begins with:

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y = 2x + 3

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Then substituting -2 for x gives:

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y = 2*(-2) + 3 = -4 + 3 = -1

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Answer:

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Step-by-step explanation:

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Answer:

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