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Leni [432]
3 years ago
13

What is the factorization of 3x2 – 8x + 5?

Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0

Answer:

(x-1)(3x-5)

Step-by-step explanation:

3x^2 - 8x + 5

To factor it we use AC or splitting the middle term method

product is 3 times 5 is 15

Sum is -8

-3 times -5 is 15

-3 plus -5 is -8

Factors are -3 and -5

3x^2 -5x-3x+ 5

Group first two terms and last two terms

(3x^2 -5x)+(-3x+ 5)

x(3x-5)-1(3x- 5)

Factor out 3x-5

(x-1)(3x-5)

Charra [1.4K]3 years ago
3 0
3x2-8x+5
=6-8x+5
=6-3x-5x+5
=3(2-x)-5(x-1)
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\large\boxed{\dfrac{x+2}{x^2-6x-16}\div\dfrac{1}{9x}=\dfrac{9x}{x-8}}

Step-by-step explanation:

\dfrac{x+2}{x^2-6x-16}\div\dfrac{1}{9x}=\dfrac{x+2}{x^2+2x-8x-16}\cdot\dfrac{9x}{1}\\\\=\dfrac{(x+2)(9x)}{x(x+2)-8(x+2)}=\dfrac{(x+2)(9x)}{(x+2)(x-8)}\\\\\text{cancel}\ (x+2)\\\\=\dfrac{9x}{x-8}

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