Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Answer:
Step-by-step explanation:
I think in this question we have to find slope, if so, its y = 10x.
to find the slope just pick two numbers, i chose (2,20) and (7,70) and then put them in the slope formula y2-y1/x2-x1. That gave me 10. I hope its correct. :)
Domain are the values of x, range are the values of y
Answer:
I'm not sure what 15y3 is, but I'll take a guess.
If the only numbers are 15, 3, and -40, then the greatest common factor is 1.
If the only numbers are 15 and 3, then it's three.
If the only numbers are 15 and -40, it would be 5.
